Question

Mass of a piece of copper is 20 g. Find the rise in temperature of the piece when 100 calorie of heat is supplied to it? Specific heat of copper = 0.09 Cal.g^-1, °C^-1​

Answer 1

Answer:

Explanation:

Letriseintemperature=θR​

Heatsuppliedtocopper=20cal​/s×120s=2400cal

Also, Heatsupplied=mcθR​

2400cal=0.12kg×100calkg−1oC−1θR​

∴θR​=2400/0.12​×100 oC=200oC

The final temperature of the copper

 =20oC+200oC

 =220oC.