A force F=( 3i + 4j)N acts on a particle moving in xy plane starting from the origin the particle first go along x-axis to the point (4,0)m and then parallel to y-axis to the point (4,3 )m the total work done by the force on the particle
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Answered by
131
Given conditions ⇒
Force = 3i + 4j
Displacement vector,
Displacement along x axis = 4i
Displacement along y axis = 3j
∴ Total displacement = 4i + 3j
From the definition of the Work, It is the Scalar or the dot product of the Force and displacement.
Using the Formula ,
∴ Work Done = F · Displacement.
= (3i + 4j) · (4i + 3j)
= 12 + 12
= 24 J.
Hence, the total work done by the particles is 24 J.
Hope it helps.
Answered by
4
Answer:answer is (3)
mark me brainliest if it helps
Explanation:displacement =4i^+3j^
Force=3i^+4j^
Work=F.d
=12+12
=24J
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