A force f=5i+6j-4k acting on a body produces a displacement s=6i+5k.find the work done by the force.
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w=Fscos°
5i+6j-4k x 6i+5k=30i+6j-20k
5i+6j-4k x 6i+5k=30i+6j-20k
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● Answer:
Work done, W = 10 joules
● Explanation:
Force acting on the object, F=5i+6j-4kF=5i+6j−4k
Displacement, d=6i+5kd=6i+5k
Work done is given by :
W=F.d
W=(5i+6j-4k).(6i+5k)
Since, i.i = j.j = k.k = 1
W=30-20
W = 10 joules
So, the work done by the force is 10 joules. Hence, this is the required solution.
Hope it helps!✔✔
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