Question

A force f=5i+6j-4k acting on a body, produces a displacement s=6i+5k work done by the force is

Answer 1

we know that
work done = force•displacement
work done = (5i+6j-4k)(6i+(0)j+5k).
work done = 30 - 20
work done = 10 Joule.

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Answer 2

Answer:

Work done, W = 10 joules

Explanation:

Force acting on the object, $F=5i+6j-4k$

Displacement, $d=6i+5k$

Work done is given by :

$W=F.d$

$W=(5i+6j-4k).(6i+5k)$

Since, i.i = j.j = k.k = 1

$W=30-20$

W = 10 joules

So, the work done by the force is 10 joules. Hence, this is the required solution.