A force F=a+bx acts on a particle in the x-direction,where a and b are constants.Find the work done by this force during a displacement from x=0 to x=d.
Answers
Answered by
3
as
work done = force× displacement
=(a+bx. × d) -( a+bx × 0)
=(a+bx)d
work done = force× displacement
=(a+bx. × d) -( a+bx × 0)
=(a+bx)d
Similar questions