Question

D is a point on the side BC of triangle ABC such that angle BAC= angle ADC. Prove that CA2 = CB x CD

Answer 1

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Answer 2

IN ΔABC AND ΔADC

∠C = ∠C (COMMON)

∠BAC =∠ADC

∴ ΔABC ≈ ΔADC (AA CRITERIA)

∴AC/DC = BC/AC (CPST)

∴CA²=CB*CD

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