A force F=-k/x square acts on a particle in x direction.find the work done by this force in displacing from x =a to x=2a
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Answered by
6
F=[-k/x]^2
Formula for work done is Force*Distance, So by putting the values...
F=-k^2(1/a^2 - 1/4a^2)
F= k^2(3/4a^2) or F= 3k^2/4a^2
Hope it Helps!!!
Answered by
5
-k/2a is your answer
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