Question

A force of 10 newton applied to a mass of x produces an acceleration of 5m/s². when the same force is applied on a mass of y it produces an acceleration of 15m/s² on that mass. what acceleration will be produced by the same force if the two masses are tied together.

Answer 1

Answer:

ANSWER IS 3.75m/s^2

Explanation:

F=10N

a1=5m/s^2

m1=F/a

m1=2kg

F=10N

a2=15m/s^2

m2=10/15=2/3

m1+m2=2+2/3=8/3

F=10N

a=10/(8/3)=10/8*3=3.75m/s^2

MARK BRAINLIEST PLEASE

Answer 2

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✦ Required Answer:

✳ GiveN:

• Force of 10 N applies to a mass of x produces an acceleration of 5 m/s^2.
• Force of 10 N applies to a mass of y produces an acceleration of 15 m/s^2.

✳ To FinD:

• Acceleration produced when both masses were tied, with same force applied....?

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✦ How to solve?

The above question is based Newton's law of motion, most prominently the Newton's 2nd law. The law states that rate of change of momentum is directly proportional to the force acting on it and acts in the same direction as force. So, we can write it as,

$\large{\ast{ \boxed{ \rm{ \purple{F\: \propto \: \frac{ \triangle \: p}{t} }}}}}$

Which can be further simplified as,

$\large{\ast{ \boxed{ \rm{ \purple{F= ma}}}}}$

By using this formula, let's solve this question.

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✦ Solution:

We have,

• Force = 10 N
• Acceleration = 5 m/s^2
• Mass = x kg

By using formula,

$\large{ \rm{ \longrightarrow \: F= ma}} \\ \\ \large{ \rm{ \longrightarrow \: 10 \: N = x \times 5m {s}^{ - 2} }} \\ \\ \large{ \rm{ \longrightarrow \: x = \cancel{\frac{10 \: N}{5 \: m {s}^{ - 2} } }}} \\ \\ \large{ \rm{ \longrightarrow \: x = 2 \: kg}}$

Next we have,

• Force = 10 N
• Acceleration = 15 m/s^2
• Mass = y kg

By using formula,

$\large{ \rm{ \longrightarrow \: F = ma}} \\ \\ \large{ \rm{ \longrightarrow \: 10 \: N = y \times 15m {s}^{ - 2} }} \\ \\ \large{ \rm{ \longrightarrow \: y = \cancel{\frac{10\:N}{15m {s}^{ - 2} } }}} \\ \\ \large{ \rm{ \longrightarrow \: y = \frac{2}{3} kg}}$

We have to find acceleration, when mass are tied together and same force is acting on it.

✏ Total mass = (2 + 2/3) kg = 8/3 kg

By using formula,

$\large{ \rm{ \longrightarrow \: F= ma}} \\ \\ \large{ \rm{ \longrightarrow \: a = \frac{F}{m} }} \\ \\ \large{ \rm{ \longrightarrow \: a = \frac{10 \: N}{ \frac{8}{3} kg} }} \\ \\ \large{ \rm{ \longrightarrow \: a = \frac{10 \times 3}{8} m {s}^{ - 2} }} \\ \\ \large{ \rm{ \longrightarrow \: a = \frac{15}{4} m {s}^{ - 2} }} \\ \\ \large{ \rm{ \longrightarrow \: a = \boxed{ \rm{ \red{3.75 \: m {s}^{ - 2} }}}}} \\ \\ \large{ \therefore{ \underline{ \underline{ \rm{ \green{Hence, \: solved \: \dag}}}}}}$

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