A room floor has 38 square shaped tiles with side 40 cm. Find the area of the floor.
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The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the ... Find the perimeter of each of the following shapes: (a) A triangle of ...
yadavchanda617:
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Given:
- 38 square tiles of side 40 cm is paved on a room's floor.
To find:
- The area of room's floor.
Formula used:
- Area of square = side × side sq.units.
Solution:
Area of a tile × 38 = Area of floor
→ (side × side) × 38 = Area of floor
→ (40 × 40) × 38 = Area of floor
→ 1600 × 38 = Area of floor
→ 60,800 cm² = Area of floor
→ 608 m² = Area of floor
Therefore, the area of room's floor is 608 m².
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Some formulas to know:-
- Area of rectangle = length × breadth sq.units
- Perimeter of square = 4 × side units
- Area of square = side × side sq.units
- Perimeter of circle = 2πr units
- Area of circle = πr² sq.units
- Perimeter of parallelogram = 2 × (a + b) units
- Area of parallelogram = base × height sq.units
- Perimeter of rhombus = 4 × side units
- Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units
- Perimeter of equilateral triangle = 3 × side units
- Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units
- Perimeter of trapezoid = (Sum of all sides) units
- Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units
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