Question

a force of 100N act on a body at a distance of 30 cm from a pivot.What is the torque acting on it​

Answer 1

Given

Force = 100 N

Distance = 30 cm

To Find

Torque

Solution

We know that

$\rm \longrightarrow \tau=F \times d$

Here

• $\rm \tau$ = Torque
• F = Force
• d = Distance

Units

• $\rm \tau$ = Newton metre (N m)
• F = Newton (N)
• d = metre (m)

According to the question

We are asked to find torque

Therefore

We must find $\rm "\tau"$

Given that

Force = 100 N

Distance = 30 cm

Hence

• F = 100 N
• d = 30 cm = 0.3 m

Substituting the values

We get

$\rm \longrightarrow \tau=100 \times 0.3 \ N \ m$

Therefore

$\rm \longrightarrow \tau=30 \ N \ m$

Hence

Torque = 30 N m

Answer 2

Answer:

Given :-

• A force of 100 N act on a body at a distance of 30 cm from a pivot.

To Find :-

• What is the torque acting on it.

Formula Used :-

✦ τ = F × D✦

where,

• τ = Torque
• F = Force
• Distance

Solution :-

Given :

• Force = 100 N
• Distance = 30 cm = 30 ÷ 100 = 0.3 m

According to the question by using the formula we get,

⇒ τ = 100 N × 0.3 m

➠ τ = 30 Nm

∴ The torque acting on it is 30 Nm .