Write the dimensions of a and b in the relation , P = (b-x^(2))/(at) , where P is power ,x is distance and t is time
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The dimensions of a = [M⁻¹T²] and b = [L²]
- It is given that power P = (b-x²) / at
⇒ P = b / at - x² / at
- This means that x²/at and b/at must have the same dimensions as the dimensions of power.
- Dimensions of power = [ML²T⁻³]
- Dimensions of distance = [L]
- Dimensions of time = [T]
- So, x²/at = [L²] / a[T] = [ML²T⁻³]
⇒ a = [M⁻¹T²]
b/at = b / [M⁻¹T²][T] = [ML²T⁻³]
⇒ b = [L²]
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