Question

A force of 10N acts on a body of mass 2kg for 3s initially at rest .Calculate the velocity acquired by the body and also calculate the change in momentum of the body​

Answer 1

answer: 15m/s ; 30kgm/s

Explanation:

given force = 10N

         FORCE = MASS x ACCELERATION

         ACCELERATION = FORCE/MASS= 10/2= 5 m/s^2

        using

       V = U + at

      where u = initial velocity

                 v = final velocity

                 a = acceleration

                 t = time

      here initial velocity= 0 (as the body was at rest )

  V = 0+ 5 x 3

     =15m/s

  momentum = mass x velocity

     change in momentum= final - initial

                      initial momentum = 0 ( as velocity was 0)

    change in momentum= final = 2 x 15 = 30kgm/s

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