Question

A force of 120 N produces an acceleration of 2m/s^2 on a mass m1 and 10m/s^2 on mass m2. What would be the acceleration if both masses are tied together and same force is applied on them.​

Answer 1

we know that,

f = m×a

therefore, m1=f÷a1

m1= 120÷2=60kg

now,

m2 = f÷a2

m2= 120÷10

m2 = 12kg

now

mass = m1+m2

mass =72kg

and force = 120N

therefore,

f=m×a

a= f÷m

a= 120÷ 72

a= 1.67(approx)( ans)

Answer 2

Answer:

Acceleration of both masses tied together is $1.67m/s^{2}$.

Explanation:

Given applied force, $F=120 N$

         acceleration of body of mass $m_{1}$,  $a_{1} =2m/s^2$

         acceleration of body of mass $m_{2}$,  $a_{2} =10m/s^2$

Force applied on a body is $F = m\times a\implies m=\frac{F}{a}$

Therefore mass of 1st body is

                                     $m_{1} =\frac{120}{2} =60kg$

                 mass of 2nd body is

                                     $m_{2} =\frac{120}{10} =12kg$

When both masses are tied together, total mass $m= m_{1} +m_{2}$

                                                                                     $= 60 +12=72kg$

When same force of 120N is applied, then the acceleration is

                                      $a= \frac{F}{m}$

                                         $= \frac{120}{72}\approx1.67m/s^{2}$

Therefore, the acceleration of both masses tied together is $1.67m/s^{2}$.