Question

question no. 2,3,4
please answer fast
tysm who r answering​

Answer 1

Answer:

(2)

AC=

$\sqrt{17 {}^{2} - 8 {}^{2} } \\ = \sqrt{25 \times 9} \\ = 15$

cosB=8/17

tan C=8/15

$sin {}^{2} b + cos {}^{2} b = ( \frac{8}{17} ) {}^{2} + ( \frac{15}{17} ) {}^{2} \\ = \frac{64 + 225}{17 {}^{2} } \\ = \frac{289}{17 \times 17} \\ = 1$

sinB cosC+cosB sinC

=(15/17)*(15/17)+(8/17)(8/17)

=289/289=1

(3)

AC=

$3 + \sqrt{12 {}^{2} - 4 {}^{2} } = 3 + \sqrt{144 - 16} \\ = 3 + \sqrt{128} = 3 + 8 \sqrt{2}$

AB=

$\sqrt{4 {}^{2} + 3 {}^{2} } \\ = 5$

cosA=3/5

cosecA=4/5

$tan {}^{2} a - sec {}^{2}a$

=(4/3)^2. - (5/3)^2

=(16/9) - (25/9)

=-1

sinC=5/(3+8√2)

secC=(3+8√2)/12

cot^2 C- cosec^2 C=(12/5)^2. - {(3+8√2)/5}^2

={144-128-9-48√2}/25

=(7-48√2)/25

Answer 2

Answer:

see the attachment

hope it helps ☺️