Question

A force of 1200N acts on the surface of area 10Cm normally. What would be the thrust and pressure on the surface

Answer 1

Thrust is equal to force acting normally.
Pressure = Thrust / Area
=1200/10
=120 N/A²

Answer 2

Hey there!

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                        = 1200 / 0.001

                       = 1200000 Pa

                       = 1.2 × 10⁶ Pa

Hope it Helps You!