Question

A force of 15 newton acts on a body of mass 5 kg. Find the acceleration produced.​

Answer 1

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Given:

Force acting on a body = 15N

Mass Of body = 5Kg

To find:

the acceleration produced = ?

Solution:

We know that ,

$\sf{force \: = mass \times acceleration} \\ \\ \sf{acceleration = \frac{force \: acting \: on \: body \: }{mass \: of \: body}} \\ \\ \sf{acceleration = \frac{ \cancel15}{ \cancel3}} \\ \\ \sf{acceleration = 5m \: per \: {sec}^{2} }$

Answer 2

Answer:

• The Acceleration (a) Produced  is 3 m/s².

Given:

1. Applied Force (F) = 15 N
2. Mass of the body (M) = 5 Kg

Explanation:

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Newton's Second Law:

It States that the rate of change of momentum of a body is directly proportional to the External force applied to it.

Expression:

• F = M a

Units:

• S.I Units = Newtons.
• C.G.S Units = dynes.

Dimensional Formula:

• M L T⁻²

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From the formula we know,

⇒ F = M a

Where,

• F Denotes Force.
• M Denotes Mass.
• a Denotes Acceleration.

Now,

⇒ F = M a

Substituting the values,

⇒ 15 N = 5 Kg × a

⇒ 15 = 5 × a

⇒ a = 15 / 5

⇒ a = 3

⇒ a = 3 m/s².

∴ The Acceleration (a) Produced  is 3 m/s².

$\rule{300}{1.5}$