Question

A force of 25 N acts for 4s on a body of mass 2 kg initially at rest. Determine
1) the acceleration produced,
2)the velocity of the body at the end of 4 s, and
3)the distance moved by it during this time (Ans. i) 12.5 ms”, ii) 50 ms'. iii) 100m)

Answer 1

Answer:

.....................................???

Answer 2

Answer:

f= m( v- u) / t

25= 2(v-0) /4

25*4/2 = v

/2 = v

v= 50

now v = 50 u= 0 t = 4

a= 50-0/4

a= 12.5

now s = ut+ 1/2 at^2

s= 0 + 1/2 *12.5 *4^2

s= 12.5/2 *16

s= 12.5*8

s=