Question

A force of 50 kg is required to pull a roller weighing 500 kg over ice .what is coefficient of friction?

Answer 1

frictional force= force * coefficient of friction

50=500*c

c=50/500

c=0.1

Answer 2

Answer:

R=mg =500×9.8N.......(i)

F=50 kgf =50×9.8N.......(ii)

From equation (i) & (ii),we get

Coefficient of friction =50/500 =0.1