Question

A force of 80 N is applied on a nail whose tip has a cross sectional area of 0.002 centimeter square calculate the pressure on the tip

Answer 1

$Force(F)=80N$

$Area(A)=2×10^{-3}cm=2×10^{-5}m$

$\blue{ \boxed{Pressure(P)=\frac{F}{A}}}$

$\implies P=\frac{80}{2 \times {10}^{ - 5} }$

$\orange{ \therefore Pressure(P)=4 \times {10}^{6} N {m}^{ - 1} }$

Answer 2

The pressure on the tip is 4 × 10⁻⁶ N/m²

The pressure on any particular given area is defined by the amount of perpendicular force applied per unit area.

So, Pressure, P = F/A   [ F = Perpendicular force applied, A = area of cross section]

Given,

Force applied on a nail (F) = 80 N

Area of cross section (A) of the tip of the nail = 0.002 cm²

                                                               = 2× 10⁻⁷ m² [∵ 1 cm² = 0.001 m²]

So, the Pressure exerted will be,

P = 80/ ( 2× 10⁻⁷) N/m²

⇒ P = 4 × 10⁻⁶ N/m²

The pressure on the nail tip is 4 × 10⁻⁶ N/m².