Question

A force of 98n is just able to move a block of mass 20 kg on a rough horizontal surface .Calculate the coefficent of friction

Answer 1

F=98N
rough surface so
F=uR
R=mg
g=10
98=u×20×10
u=49/100
u=0.49
where u= coefficient of friction

Answer 2

Hello ☺

________________rrjack29 ❤ here

___________Answer ⤵⤵⤵

Given,

↪ Force applied to move = 98 N
↪ Mass of Block = 20 kg 

F = Mass × acceleration 

　◾　F = ma 


= mg

= 20 × 9.8

= 196 N

As, Fk ​=98N 

Then,

μ = 1/2

♦ So the value of coefficient of friction = 1/2