A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate?
Answers
Answered by
1
Force= 1020N
Displacement= 3.50m
Work done= Force×Displacement
= 1020×3.50 J
= 3570 J or 3.57kJ
Similar questions