Question

a fort had provisions for 450 soldiers for 40 days. after 10 days 90 more soldiers come to the fort . find in how many days will the remaining provisions last at the same rate

Answer 1

Solution:-
Total period = 40 days
After 10 days this period will be = 40 - 10 = 30 days.
Number of soldiers in the beginning = 450
Number of soldiers arrive = 90
Total soldiers = 450 + 90 = 540
Number of soldiers                Number of days
    450                                             30
    540                                              x  
Number of soldiers increases than the food will last for lesser days. This an inverse proportion.
450 : 540 :: 30 : x
x = (450*30)/540 
x = 25 
So, the remaining provision will last for 25 days at the same rate.
Answer

Answer 2

Answer:

After 10 days this period will be = 40 - 10 = 30 days.

Number of soldiers in the beginning = 450

Number of soldiers arrive = 90

Total soldiers = 450 + 90 = 540

Number of soldiers                Number of days

   450                                             30

   540                                              x  

it is inverse propotion so,

450/540=x/30

450/540*30=x

x=25

therefore number of days = 25