Question

A frame 110010111001 is to be transmitted using the crc with generating poly x3+x+1 to protect it from errors. what is the transmitted frame

Answer 1

Suppose the length of a 10Base5 cable is 2500 metres. If the speed of propagation in a
thick coaxial cable is 200,000,000 m/s how long does it take for a bit to travel from the
beginning to the end of the network? Assume that there is a 10s delay in the
equipment.
Answer:
10Base5 has a maximum length of 500 metres so repeaters should be inserted into the
cable in order to ensure transmission is possible over the full length of the 2500m cable.
4 repeaters are required as shown below:
Recommended answer is 4 x 10s + 2500/200,000,000 = 52.5s, but other answers will
be accepted with suitable arguments.
1.2 The data rate of 10Base5 is 10Mbps. How long does it take to create the smallest
frame? Show your calculations.
Answer:
The smallest frame is 64 bytes or 512 bits. With a data rate of 10 Mbps, we have
Tfr = (512 bits) / (10 Mbps) = 51.2 μs
This means that the time required to send the smallest frame is the same at the
maximum time required to detect the collision