Question

A freely falling object falls through a height h in the nth second. what is the fall of height in the next second?
A.h-g
B.hg
C.h+g
D.h/g

Answer 1

Answer is C (h+g). this may help you my friend.

Answer 2

Statement of the given problem,

A freely falling object falls through a height h in the end second. What is the fall of height in the next second?

Let at Nth second the freely falling object falls through the height h.

Hence from above data we get following kinematic relation,

h = 0 + (1/2)*g*(2*N - 1) [g = gravitational acceleration]

or 2*N - 1 = 2*h/g or N = h/g + 1/2 …… (1)

Therefore the fall of height in the (N + 1)th second [next second]

= 0 + (1/2)*g*[2*(N + 1) - 1]

= (1/2)*g*(2*N + 1) = (1/2)*g*[2*(h/g + 1/2) + 1] [from (1)]

= g*(h/g + 1) = h + g [Ans]