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angle q is 90 degree as tangents are perpendicular to the radius
so the angle qpq = 20
and angle qpr =40
so the angle qpq = 20
and angle qpr =40
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triangleQPO n ORP are congurent by SSS so by c.p.c.t angel QOP = POR =70
then ORQ=140
NOW.. WE KNOE THAT POQR IS QUADRILATERAL
SUM OF ANGEL =360
ANGLE P + Q + R + O =360
90 + 90 + 140 + P =360
320 + P = 360
P = 360 -320
P = 40
then ORQ=140
NOW.. WE KNOE THAT POQR IS QUADRILATERAL
SUM OF ANGEL =360
ANGLE P + Q + R + O =360
90 + 90 + 140 + P =360
320 + P = 360
P = 360 -320
P = 40
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