a frog hops along as straight line path from point 'A'to point 'B' in 10 second and then turns and hops to point 'C' in another 5 second .calculate the average speed and average velocity of the frog for the motion between.
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Answered by
92
Let distance from A to C=x m.
Let distance from B to C=y m.
Average speed=m/s(x+y)/(15)=(x+y)/15 m/s
Displacement=x m along A to C
Average Velocity=x/15 m/s
Let distance from B to C=y m.
Average speed=m/s(x+y)/(15)=(x+y)/15 m/s
Displacement=x m along A to C
Average Velocity=x/15 m/s
shaggyy:
Hey!! This question was in SA I of Science, wasn't it?? :o
Answered by
10
Answer:
Let the distance from a to c=x m.
Let thedistance from b to c=y m.
Average speed=m/s(x+y)/(15)=(x+y)/15 m/s
Displacement=x m along a to c
Average Velocity=x/15 m/s
avg.speed=(x+y)15 m/s
avg.velocity=x/15 m/s
Explanation:
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