a fruit seller bought apples for rupees 1200 write the cost price of each apple in terms of X If 10 of the Apples were rotten and he sold each of the rest at rupees 10 more than the cost price of each write the selling price of x-10 apples if he had made profit of 60 rupees in this transaction form an equation in x solver to evaluate x
Answers
Let the number of apples bought be x then the cost price of each apple is
1200/x
If 10 rot the new number is x - 10
The selling price for the remaining apples is 1200 + 60 = 1260
1260/(x - 10) is the selling price of each apple.
This is equivalent to the cost price plus 10 which is as shown :
1200/x + 10
To solve for x, we equate the two.
That is :
1200/x + 10 = 1260 / (x - 10)
1200 (x - 10) + 10x (x - 10) = 1260x
1200x - 12000 + 10x² - 100x = 1260x
1260x - 1200x + 100x - 10x² + 12000 = 0
10x² - 160x - 12000 = 0
Dividing through by 10 we have :
x² - 16x - 1200 = 0
From this we solve for x using quadratic formula.
The equation is thus :
x² - 16x - 1200 = 0
Answer:
x² - 16x - 1200 = 0
Step-by-step explanation:
1200/x
If 10 rot the new number is x - 10
The selling price for the remaining apples is 1200 + 60 = 1260
1260/(x - 10) is the selling price of each apple.
This is equivalent to the cost price plus 10 which is as shown :
1200/x + 10
To solve for x, we equate the two.
That is :
1200/x + 10 = 1260 / (x - 10)
1200 (x - 10) + 10x (x - 10) = 1260x
1200x - 12000 + 10x² - 100x = 1260x
1260x - 1200x + 100x - 10x² + 12000 = 0
10x² - 160x - 12000 = 0
Dividing through by 10 we have :
x² - 16x - 1200 = 0
From this we solve for x using quadratic formula.
The equation is thus :
x² - 16x - 1200 = 0