a fruit vendor buys oranges at 6 for rs 10 and an equal number at 10 for rs 20. he mixes them and sells at Rs 21.60 per dozen. find his gain or loss percent.
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NO OF ORANGES HE BOUGHT =6+10=16
TOTAL COST=10+20=RS.30
C.P OF EACH ORANGES IS 30/16
NOW HE SELLS IT AT RS.21.6 FOR 12
S.P OF ORANGES=21.6/12
SINCE 30/16 IS GRATER THAT 21.6/12
HE HAD A LOSS
THE LOSS =30/16-21.6/12=RS 3.6
TOTAL COST=10+20=RS.30
C.P OF EACH ORANGES IS 30/16
NOW HE SELLS IT AT RS.21.6 FOR 12
S.P OF ORANGES=21.6/12
SINCE 30/16 IS GRATER THAT 21.6/12
HE HAD A LOSS
THE LOSS =30/16-21.6/12=RS 3.6
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Answer:
Required Answer :
Given,
A fruit vendor has to purchase equal number of oranges.
Selling price per dozen = ₹21.60
So he have purchased 6 oranges, Each from two cases.
Case (i) :
Cost of 6 orange = ₹10
Case (ii) :
Cost of 10 oranges = ₹20
_________________________
Cost of 6 oranges are given by,
× 6
= ₹12.
_________________________
So Total cost of 1 dozen Becomes,
10+12
= ₹ 22
_________________________
Now we can see that,
Cost price > Selling price
_________________________
We need to find the loss percentage;
Loss = Cost price - Selling price
Loss = 22 - 21.60
Loss = 0.40
_________________________
Now we need to find Loss percentage;
Loss % = × 100
Loss % = × 100
Loss% = 1.81%
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