Math, asked by singhamaPAndrif, 1 year ago

a fruit vendor buys oranges at 6 for rs 10 and an equal number at 10 for rs 20. he mixes them and sells at Rs 21.60 per dozen. find his gain or loss percent.

Answers

Answered by Anonymous
1
NO OF ORANGES HE BOUGHT =6+10=16
TOTAL COST=10+20=RS.30
C.P OF EACH ORANGES IS 30/16
NOW HE SELLS IT AT RS.21.6 FOR 12
S.P OF ORANGES=21.6/12
SINCE 30/16 IS GRATER THAT 21.6/12
HE HAD A LOSS
THE LOSS =30/16-21.6/12=RS 3.6
Answered by anushkawaghmare2610
0

Answer:

Required Answer :

Given,

A fruit vendor has to purchase equal number of oranges.

Selling price per dozen = ₹21.60

So he have purchased 6 oranges, Each from two cases.

Case (i) :

Cost of 6 orange = ₹10

Case (ii) :

Cost of 10 oranges = ₹20

_________________________

Cost of 6 oranges are given by,

× 6

= ₹12.

_________________________

So Total cost of 1 dozen Becomes,

10+12

= ₹ 22

_________________________

Now we can see that,

Cost price > Selling price

_________________________

We need to find the loss percentage;

Loss = Cost price - Selling price

Loss = 22 - 21.60

Loss = 0.40

_________________________

Now we need to find Loss percentage;

Loss % =  × 100

Loss % =  × 100

Loss% = 1.81%

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