Math, asked by tahir6705, 1 year ago

A fruit vendor buys oranges at 6 for Rs 10 and an equal number at 10 for rupees 20.he mixes them and sells at rupees 21.60 . find his gain or loss percent

Answers

Answered by ashuboss219
11
Cost price of six oranges = rs10
cost price of 1 orange = rs10/6
cost price of 10 orange = rs20
cost price of 1 orange = rs20/10
= rs2
total cost price = rs2+rs10/6
= rs22/6
selling price of 1 dozen = rs 21.60
as we all know that 1 dozen = 12
therefore, selling price of 1 orange = rs 21.60/12
= rs 1.8 or 216/120
as we can see that cost price is greater, therefore loss is made.
loss = cost price - selling price
= 22/6-216/120
= rs 224/120
loss % = loss/cost price ×100 ( it is a formula )
= 224/120/22/6
= 224×6/120×22 ×100
= 50.9%
Answered by roshankale00000
5

Step-by-step explanation:

orange at 6 for rs 10

and orange at 10 for rs 20

price of 1 orange is rs 2

so 6 orange at 10 rupees and remaining 6 at 12 rupees

so

cost price of 12 orange is 22 rupees

selling price of 12 orange is 21.60 rupees

loss = c.p - s.p = 22.00 - 21.60 = 0.40 rupees

loss percent = ( loss / c.p * 100)

= (0.40 / 22 * 100 ) = (40/22) = 20/11

Is the right answer.

Similar questions