Question

A fruit vendor has 24 kg. apples. he sold some apples at a profit of 20% and remaining at a loss of 5 % . if he got 10 % profit on the whole transaction then how much apples did he sell at loss?

Answer 1

The quantity of apples that the vendor sold at 5% loss is 9.6 kg.

• A fruit vendor has 24 kg apples.
• Let the quantity of apples sold by the vendor at 20% profit be x.
• Therefore, the remaining apples sold at 5% loss will be 24-x.
• If he got 10% profit on whole transaction, then we have to find how much apples did he sell at 5% loss.
• Let cost price of the apples per kg be m.
• Amount the got be selling apples at 20% profit = 1.2xm
• Now amount he got by selling apples at 5% loss = 0.95m(24-x) = 22.8m -0.95mx
• Now the amount he got by selling total number of apples = 1.1×24m

The equation becomes,

1.2xm + 22.8m - 0.95xm = 26.4m

1.2x - 0.95x =3.6

x = 14.4 kg

• Quantity of apples that he sold at 20% profit is 14.4 kg.
• Therefore, Quantity of apples he sold at 5% loss is 24-14.4 = 9.6kg.

Answer 2

The fruit vendor sold 9.6 kg of apples at loss.

Step-by-step explanation:

Given:

A fruit vendor has 24 kg apples.

He sold some apples at a profit of 20% and remaining at a loss of 5 %.

if he got 10 % profit on the whole transaction then how much apples did he sell at loss .

Solution:

Let the number of apples be x sold at 20% profit

Remaining apples are sold at 24 – x at 5% profit

Total profit = 10%

X $\times$ 20% (24-x) $\times$ 5% = 24 $\times$ %

X= 14.4 kg

Apples sold at 5% loss= 24- 14.4 = 9.6 kg

To know more:

A man sold an article at a loss of 20 % . If he sell the article for 12 rupees more he would have gain 10% .The cost price of article is :

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