A fruit vendor has 24 kg. apples. he sold some apples at a profit of 20% and remaining at a loss of 5 % . if he got 10 % profit on the whole transaction then how much apples did he sell at loss?
Answers
The quantity of apples that the vendor sold at 5% loss is 9.6 kg.
- A fruit vendor has 24 kg apples.
- Let the quantity of apples sold by the vendor at 20% profit be x.
- Therefore, the remaining apples sold at 5% loss will be 24-x.
- If he got 10% profit on whole transaction, then we have to find how much apples did he sell at 5% loss.
- Let cost price of the apples per kg be m.
- Amount the got be selling apples at 20% profit = 1.2xm
- Now amount he got by selling apples at 5% loss = 0.95m(24-x) = 22.8m -0.95mx
- Now the amount he got by selling total number of apples = 1.1×24m
The equation becomes,
1.2xm + 22.8m - 0.95xm = 26.4m
1.2x - 0.95x =3.6
x = 14.4 kg
- Quantity of apples that he sold at 20% profit is 14.4 kg.
- Therefore, Quantity of apples he sold at 5% loss is 24-14.4 = 9.6kg.
The fruit vendor sold 9.6 kg of apples at loss.
Step-by-step explanation:
Given:
A fruit vendor has 24 kg apples.
He sold some apples at a profit of 20% and remaining at a loss of 5 %.
if he got 10 % profit on the whole transaction then how much apples did he sell at loss .
Solution:
Let the number of apples be x sold at 20% profit
Remaining apples are sold at 24 – x at 5% profit
Total profit = 10%
X 20% (24-x) 5% = 24 %
X= 14.4 kg
Apples sold at 5% loss= 24- 14.4 = 9.6 kg
To know more:
A man sold an article at a loss of 20 % . If he sell the article for 12 rupees more he would have gain 10% .The cost price of article is :
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