Question

A garden 175 m by 100 m has 2 paved crossroads in its Centre . if each road is 4 m wide find the total area of the crossroads​

Answer 1

Answer:

MATHS

Two cross roads, each of width 5 m, run at the right angles through the centre of a rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find the area of the roads. Also find the cost of constructing the roads at the rate of Rs.105 per m

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ANSWER

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answer 2

Answer:

hii..

here is ur solution..

Step-by-step explanation:

Given..

Length of garden 175m

Breadth of garden 100m

and two paved crossroads of 4m wide each in its center..

to finde the total area of the crossroads we have to find the are of both crossroad and add both ...

Area of first cross road= l*b

= 100*4

=400m^2

Area of second crossroad-

=175*4

=700m^2

=400m^2 + 700m^2

=1100m^2

hope it helps u....