Question

A garden roller is 22cm in diameter and 63 cm in width what are will be covered in 200 revolution

Answer 1

Given,

width = 63 cm
Diameter = 22cm
So, Radius(r) = 22/2 = 11 cm

Curved Surface Area of the roller =
2πrh
= 2 * 22/7 * 11 * 63

$= 4356 \: {cm}^{2}$
This is area covered in one revolution.

Therefore, the area covered in 200 revolutions is ---

4356 x 200 cm^2 = 8,71,200 cm^2

Hope this helps you.

Answer 2

$\huge{\underline{\sf{Question :-}}}}$

A garden roller is 22cm in diameter and 63 cm in width. How much area will be covered in 200 revolution?

$\huge{\underline{\sf{Answer :-}}}}$

$\sf Given\begin{cases} &\sf{Diameter\;of\;the\; garden\:roller,\:D\;=\be{22\:cm}}\\&\sf{Width\;of\;the\;garden\: roller,\:h=\;\bf{63\:cm}}\end{cases}$

$\boxed{ \sf \red{ To \: Find : }}$

✏ Area it will cover in 200 revolutions = ❓

$\green{\underline\bold{We \:know\:,}}$

✏ Radius, r = $\frac{Diameter}{2}$

✏ r = $\frac{22}{2}$

✏ r = 11 cm

$\green{\underline\bold{From\:the\:formula,}}$

$\boxed{ \sf \blue{Area \: of\:the\:roller=\: Curved\:surface\:area\:of\:the\:cylinder }}$

= 2Πrh

= 2 × $\frac{22}{7}$ × 11 × 63

= 44 × 99

= 4356 cm sq.

$\green{\underline\bold{Now,}}$

$\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\: 1 \:revolution=\:area\:of\:the\:roller }}$

= 4356 cm sq.

$\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\:200 \:revolutions= }}$

= 200 × 4356

= 871200 cm sq.

= 87.12 m sq.

$\pink{\underline\bold{∴The\:required\:answer\:is\: = \: 87.12\: m\: sq.}}$

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