Question

A gardener moves a lawn roller through a distance of 100 m with a force of 50 N. Calculate his wages, if he is to be paid 10 paise for doing 25 J of work. It is given that applied force is inclined at 60° to the direction of motion.​

Answer 1

Given :

• Distance, s = 100 m
• Force, F = 50 N
• Inclined angle, θ = 60°
• Money getting per 25 J of work = 10 paise

To Find :

• Wages of worker = ?

Solution :

We know that :

$\underline{\boxed{\pink{\bf Work \: done = Force \times \times distance \times cos\theta}}}$

By filling values :

$\sf : \implies W = 50 \times 100 \times cos 60\degree$

$\sf : \implies W = 5000 \times \dfrac{1}{2}$

$\sf : \implies W = \cancel{\dfrac{5000}{2}}$

$\sf : \implies W = 2500J$

Now, Wages for 25 J of work = 10 paise = Rs. 0.1

$\sf : \implies Wages \: for \: 2500J \: of \: work =Rs. \: \dfrac{0.1}{25} \times 2500$

$\sf : \implies Wages \: for \: 2500J \: of \: work =Rs. \: \dfrac{1}{250} \times 2500$

$\sf : \implies Wages \: for \: 2500J \: of \: work =Rs. \: \cancel{\dfrac{2500}{250}}$

$\sf : \implies Wages \: for \: 2500J \: of \: work = Rs. \: 10$

$\underline{ \sf Hence, \: Wages \: of \: gardener \: are \: \pink{Rs. \: 10}}$

Answer 2

Answer:

A gardener moves a lawn roller through a distance of 100 m with a force of 50 N. Calculate his wages if he is to be paid 10 paise for doing 25 J of work. It is given that the applied force is inclined at 60° to the direction of motion.