a gardner roller has a diameter of 0.7m.how many revolutions does it make in 22m ?
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Answered by
0
Given the diameter of a roller = 0.7m.
Then the radius will be r = d/2
= 0.35m.
We know that CSA of a cylinder = pir^2h
= 2 * 22/7 * (0.35)^2
= 2 * 22 * 0.0175
= 0.77 m^2.
Given that Number of revolutions = 22.
Hence the number of revolutions will be = 22 * 0.77
= 16.94m^2.
Hope this helps!
Then the radius will be r = d/2
= 0.35m.
We know that CSA of a cylinder = pir^2h
= 2 * 22/7 * (0.35)^2
= 2 * 22 * 0.0175
= 0.77 m^2.
Given that Number of revolutions = 22.
Hence the number of revolutions will be = 22 * 0.77
= 16.94m^2.
Hope this helps!
Avi11111111:
hey bro I think you miss understand the question
He asked about rotation
not about its area covered
Ohkkkk..Thanks for the help bro..
please have a look upon it
ohkk
Answered by
2
1 revolution= 2πr m covered
=2*(22/7)*0.35
=2.2m covered in one revolution....
for 22 m no of revolution....
=22/2.2
=10 revolutions.....
Hope it may help you
=2*(22/7)*0.35
=2.2m covered in one revolution....
for 22 m no of revolution....
=22/2.2
=10 revolutions.....
Hope it may help you
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