Question

A gas absorbs 100 J of heat and expands against constant external pressure of
1 atm from a volume of 1 lit to 10 lit, then the change in internal energy will be (1
atm t = 100 J)
-91
-800 J
-109 J
1000​

Answer 1

Answer:

-800J

Explanation:

work done= - P∆V

= -1×(10-1)

= -9 L-atm

= -100 ×9 J

= -900J

now,

∆U = q+w

= 100 - 900

= -800 J