Math, asked by muralikrishna757, 1 year ago

A gas contained in a cylinder is compressed, the work required for compression being 5000 kj. During the process, heat interaction of 200 kj causes the surroundings to be heated. The change in internal energy of the gas during the process is

Answers

Answered by Chinmay47
0
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Answered by throwdolbeau
0

Answer:

The change in internal energy of the gas during the process is 3000 kJ

Step-by-step explanation:

The gas is compressing the cylinder , so the work done is negative and is equal to : dW = - 5000 kJ

The surrounding is being heated , so the heat is taken as negative and is equal to : dQ = - 2000 kJ

dU = change in internal energy

Now, According to the first law of thermodynamics

dQ = dW + dU

On substituting the above values in the equation, We get

- 2000 = - 5000 + dU

dU = 5000 - 2000

dU = 3000 kJ

Hence, The change in internal energy of the gas during the process is 3000 kJ

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