A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm .The pressure gauge of the cylinder indicates 12atm at 27°c .Due to sudden fire in the building the temperature start rising.At what temperature will the cylinder burst
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Explanation:
P
1
=12bar,T
1
=27+273=300K
P
2
=14.9 bar,T
2
=?
Applying pressure temperature law,
P
2
P
1
=
T
2
T
1
or T
2
=
P
1
T
1
×P
2
Substituting the values in the above equation,
T
2
=
12
300×14.9
=372.5K
Temperature in
0
C=372.5−273=99.5
∘
C
Hence the cylinder will explode at a temperature 99.5
∘
C
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