Question

A group of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from given group

Answer 1

Answer:

360 ways

Step-by-step explanation:

Ways of selecting men = 6

Ways of selecting women = 12

Ways of selecting child = 5

Total ways = 6×120×5=360 ways

Answer 2

Answer:

31 ways

Step-by-step explanation:

2 men can be selected from 4 men in $4C_{2} = \frac{4(3)}{2} = 6$ ways.

3 women can be selected from 6 women in $6C_{3} = \frac{(6)(5)(4)}{(3)(2)(1)} = 20$ ways.

1 child can be selected from 5 children in $5C_{1} = 5$ ways.

Hence, the total number of ways = 6 + 20 + 5 = 31.