Question

A gas is allowed to expand in a well insulated container
against a constant external pressure of 2.5atm from an initial
volume of 2.50 L to a final volume of 4.50L. The change in
internal energy DU of the gas in joules will be:- [2017]
(a) – 500J (b) – 505J
(c) + 505J (d) 1136.25J

Answer 1

Answer:

The correct answer is option b) – 505J

Answer 2

The internal energy of the gas in joules will be -505 J.

step by step explanation:

The given system is in isolated system.

And the condition is adiabatic process.

For adiabatic process,

q = 0

The internal energy is calculated by the following formual.

                         $\bold{\Delta U = q+W}$ ...................(1)

rearrange the equation is as follows.

                          $w=-p\Delta V$.....................(2)

From the given,

Pressure   = 2.5

Volume change = 4.5 - 2.5 =  2L.

Substitute the given values in equation (2)

                              $\Rightarrow -2.5\times 2.1$

                             $\Rightarrow 5\times 101.3J$

                             $\Rightarrow -505J$

Therefore, The internal energy of the gas in joules will be -505 J.

Hence, correct option is "b".

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