Question

The equilibrium constant for a reaction A+ 2B ⇋ 2C
is 40. The equilibrium constant for reaction
C ⇋ B + 1/2 A is
(a) 40 (b) (1/40)²
(c) 1/40
(d) (40)¹/²

Answer 1

The equilibrium constant for reaction  C ⇋ B + 1/2 A K = 1 / (40)^1/2

Option (B) is correct.

Explanation:

A + 2B ⇔ 2C       ------(1)

Equilibrium constant "K" = 40  

The equilibrium constant fro the reaction

And for C ⇔ B + 1 / 2 A  -----(2)

K1 = ?

K = 1 / √k = 1 / (40)^1/2

Thus the equilibrium constant for reaction  C ⇋ B + 1/2 A K = 1 / (40)^1/2

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4 moles of A are mixed with 4 moles of B. At, equilibrium for the reaction A+B⇄C+D, 2 moles of C and D are formed. The equilibrium constant for the reaction will be ?

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