Question

A gas occupies 500cm^3 at 27°©. calculate it volume at 40°© constant pressure

Answer 1

Answer:

521.67cm^3

Explanation:

v1=500cm^3

t1=300k

t2=313k

put on formula

V1/t1=V2/t2

answer would be 521.67cm^3

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Answer 2

GIVEN :-

• A gas occupied 500 cm³ volume at 27°C (At constant pressure)

TO FIND :-

• Volume occupied by the gas at 40°C

SOLUTION :-

We have ,

• V₁ = 500 cm³ , T₁ = 27°C = 273 + 27 = 300K
• V₂ = ? , T₂ = 40°C = 273 + 40 = 313 K

According to charle's law ,

$\large {\underline {\boxed { \bigstar{ \red{\sf{ \: \frac{V_1}{T_1} = \frac{T_2}{T_2} }}}}}}$

$\implies \sf \: \frac{500}{300} = \frac{V_2}{313 } \\ \\ \implies \sf \: \frac{5 \cancel{00}}{3 \cancel{00}} = \frac{V_2}{313} \\ \\ \implies \sf \: \frac{5}{3} = \frac{V_2}{313} \\ \\ \implies \sf \: 313 \times 5 = 3V_2 \\ \\ \implies \sf \: V_2 = \frac{313 \times 5}{3} \\ \\ \implies {\underline {\boxed {\blue{\sf {\: V_2= 521.6 \: cm {}^{3} }}}}}$

∴ The volume occupied by the gas at 40°C is 521.6 cm³