Chemistry, asked by rahul7411, 10 months ago

A gas phase reaction R-A + B + C + D is of first
order. The initial pressure was to where pressure
after 10 minutes was y. The correct expression for
rate constant k is

Answers

Answered by Mohbro
5

Answer:

Explanation:

R- A+B+C+D

P at

T equals 0 0 0 0 0

AT TIME T $- g g g g g

Attachments:
Answered by abdulraziq1534
0

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that A gas phase reaction R-A + B + C + D is of first order.

To Find:-

We have to find that the correct expression for rate constant k is

Solution:-

According to the problem

$R \rightarrow A+D+C+D$

$x_{0}-0+4a=7$

x_{0}+3 a+y

\frac{[x \mid[5][C][x]}{[n]}-\frac{0}{-8}\\\int 2.3 .3 \log \left(R \frac{R}{R}\right)=k\\8.303 \log \left(\frac{x_{0}}{x_{0}-0}\right)=1 e(10)\\k=\frac{2-303}{10}\left(\log \left[\frac{x_{0}-9}{4 x_{0}-3}\right]\right)\\k=\frac{2.303}{16} \log \left(\frac{7 r_{0}}{4 x_{0}-y}\right)

Final Answer:-

The correct expression for rate constant k is \frac{2.303}{16} \log \left(\frac{7 r_{0}}{4 x_{0}-y}\right).

#SPJ3

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