A gas 'X' is collected over water at 17 degree Celsius and 750mm pressure.If the volume of the gas collected is 50cc calculate the volume of the dry gas at s.t.p[At 17 degree celsius the vapour pressure is 14mm.]
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Answered by
141
We will use the following relation
P1V1/T1 = P2V2/T2 (1)
We are given that P1 = 750 + vapour pressure of the gas
= (750 + 14) mm of Hg
= 764 mm of Hg
T1 = 170 C = (273+ 17) K = 290K
V1 = 50 cm3
We know that at STP conditions pressure = 1atm = 760 mm of Hg and temperature = 273 K
Hence P2 = 760 mm of Hg and T2 = 273 K
Substituting the above values in equation (1), we get
V2 = (764 X 50 X 273) / (760 X 290)
= 47.32 cm3
✌️☺️
P1V1/T1 = P2V2/T2 (1)
We are given that P1 = 750 + vapour pressure of the gas
= (750 + 14) mm of Hg
= 764 mm of Hg
T1 = 170 C = (273+ 17) K = 290K
V1 = 50 cm3
We know that at STP conditions pressure = 1atm = 760 mm of Hg and temperature = 273 K
Hence P2 = 760 mm of Hg and T2 = 273 K
Substituting the above values in equation (1), we get
V2 = (764 X 50 X 273) / (760 X 290)
= 47.32 cm3
✌️☺️
Answered by
34
Answer:
45.58cc
Explanation:
see this attachment
Attachments:
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