a girl of mass 40 kg jumps on cart of 300 kg moving with 90 m/s and initial velocity of girl is 20 m/s calculate the following velocity
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Let 'v' be the velocity of the girl on the cart as the cart starts moving
The total momenta of the girl and the cart before the interaction = 40kg*5m/s + 3kg*0m/s
Total momenta after the interaction
=(40+3)kg*v m/s
=43vkgm/s
According to the law of conservation of momentum, the total momentum is conserved during the interaction
That is
43v = 200
It implies that v= 200/43 = +4.65m/s
The girl on the cart would move with a velocity of +4.65m/s in the direction in which the girl jumped
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