Question

A given charge situated at certain distance from a short electric dipole in the end on position experience a force f if the distance of the charge is double the force acting on the charge will be

Answer 1

Answer:

  F  ∝ 1/8

Remark: A pair of equal and opposite charges separated at some distance a.

And can be given as p = q.a

Explanation: Dear Student,

Force on charge in terms of dipole can be given as,

$F=qE_{a}$

$F = q*\frac{k.2p}{r^{3} }$

 F ∝ $(\frac{1}{r^{3} })$

If the distance is doubled

F ∝ $(\frac{1}{(2r)^{3} })$

 F ∝ $(\frac{1}{(2r)^{3} })$

 F  ∝ 1/8

Hope it helps

With Regards

       

Answer 2

Answer:

The new force acting on the charge will be $\dfrac{1}{8}F$.

Explanation:

Given that,

A given charge situated at certain distance from a short electric dipole in the end on position experience a force F.

Let the dipole moment be p and the charge be q placed at the distance r from the dipole.

The electric field due to the dipole at an axial point is

$E =\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{r^3}$

The force on charge q at a distance r will be

$F = qE$

$F = q\times\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{r^3}$

If the distance of the charge is double

The new force will be

$F'=q\times\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{(2r)^3}$

$F'=\dfrac{1}{8}F$

Hence, The new force acting on the charge will be $\dfrac{1}{8}F$.