a glass Sphere in is equal to (1.5 )4 CM in diameter has a Luminous embedded inside the sphere 1cm
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Given:
The glass refractive index is μ=1.5
The air refractive index is μ'=1
The diameter of sphere is d=4 cm
The radius of the sphere is R=d/2=2 cm
The embedded inside length is u= 1 cm
To find:
The apparent depth of the surface.
Solution:
Applying the refractive index formula
μ'/v -μ/u=(μ' - μ)/R
Putting the above values
1/v-1.5/1=(1-1.5)/2
1/v-1.5=0.5/2
1/v=0.25+1.5
1/v=1.75
v=1/1.75
v=0.57
So the apparent depth is at distance of 0.57
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