A golf ball has a mass of 40g and a speed of 45 m/s. if tge speed can be meaured within accuracy of 2% calculate the uncertainty in position
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Answered by
400
Use Heisenberg's uncertainty principle,
e.g., ∆x = h/4πm∆v
Here, ∆x is the uncertainty in position
∆v is the uncertainty in velocity
m is the mass of Particle .
Given, m = 40g = 0.04kg
∆v = 2% of v = 2 × 45/100 = 0.9 m/s
h = 6.626 × 10⁻³⁴ J.s
Now, ∆x = 6.626 × 10⁻³⁴/(4 × 3.14 × 0.04 × 0.9)
= 14.654 × 10⁻³⁴ m
Hence, uncertainty in position = 1.4654 × 10⁻³³ m
e.g., ∆x = h/4πm∆v
Here, ∆x is the uncertainty in position
∆v is the uncertainty in velocity
m is the mass of Particle .
Given, m = 40g = 0.04kg
∆v = 2% of v = 2 × 45/100 = 0.9 m/s
h = 6.626 × 10⁻³⁴ J.s
Now, ∆x = 6.626 × 10⁻³⁴/(4 × 3.14 × 0.04 × 0.9)
= 14.654 × 10⁻³⁴ m
Hence, uncertainty in position = 1.4654 × 10⁻³³ m
danish5478:
can please explain the calculation its so hard for me ?
Answered by
60
Answer:
Explanation:
∆v = 45X 2/100 = 0.9m/s
m= 40g = 4X 10^-2kg
now
∆x = 6.626 X 10 ^ -34/(4 X 3.14X 4 X 10^-2X 0.9)
= 1.46 X 10^ -33 m
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