Math, asked by sunilrathore9565, 1 year ago

After receiving 2 successive raises, hursh's salary became equal to 15/8 times of initial salary. by how much percent was the salary raised the first time if the second raise was twice as high (in percent) as the first?

Answers

Answered by Akash7766
46
Let Initial salary = X

First raised salary % = Y

Second raised salary % = 2Y

As per problem

==> X *  (100+Y)/100  * (100+2Y)/100  = 15/8 * X

==> (100+Y)*(100+2Y) = 15/8 * 100 *100

==> 2Y^2 + 300Y - 8750 = 0

==> Y = 25

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