Chemistry, asked by smoolya, 8 months ago

A graph is plotted between logV(lit) on y-axis and logT(K) on x-axis at a constant pressure of 0.0821 atm, for 2 moles of gas. Find the ratio between V and T? (A) 2 (B)4 (C)6 (D)7 ​

Answers

Answered by tsgjanaksharma13
0

Answer:

A graph is plotted between logV(lit) on y-axis and logT(K) on x-axis at a constant pressure of 0.0821 atm, for 2 moles of gas. Find the ratio between V and T? (A) 2 (B)4 (C)6 (D)7

Explanation:

I don't know

Answered by probrainsme104
0

Concept:

Ideal gas law is additionally called the overall gas equation is that the equation of state of a hypothetical or perfect gas. it's a decent approximation of the behaviour of the many gases under certain conditions.

Given:

We are given a graph is plotted between \log V on y- axis and \log T on x-axis.

Find

We have to search out the ratio between V and T.

Solution

Ideal gas equation could be a combination of Boyles’s law, Charles’ law, Avogadro’s law and Gay-Lussac’s law. the best gas law is written as:PV=nRT; where P,V,T and nare pressure, volume, moles and temperature.

Here, P and n are given as 0.0821 atm and 2mol. aside from pressure, R and n, other quantities are variable. The graph has to be plotted in between the variable quantities only.

First put the values given the ideal gas equation, 0.0821\timesV=2\times0.0821\times T; the term0.0821 is canceled with one another, the equation is now,V=2T.

Now, divide both sides by T, we get

\begin{aligned}\frac{V}{T}&=\frac{2T}{T}\\ \frac{V}{T}&=2\end

Thus, the ratio between V and T  is 2.

Hence, option (A) is correct.

#SPJ3

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