A greengrocer was selling apple at a penny each, chickoos at 2 for a penny and peanuts at 3 for a penny. a father spent 7 pennies and got the same amount of each type of fruit for each of his three children. what did each child get?
Answers
The father had 7 pennies. He has three children.
So whatever fruits he purchases must be in multiples of 3.
The cost of 1 apple is 1 penny.
The smallest multiple of 3 divisible by 1 is 3.
So he needs to purchase at least 3 apples for 3 pennies.
The cost of 2 chikoos is 1 penny.
The smallest multiple of 3 divisible by 2 is 6.
The cost of 6 chikoos shall be 3 pennies.
3 Peanuts we already get for 1 penny.
Now 3 apples, 6 chikoos and 3 peanuts shall cost 3 + 3 + 1 = 7 pennies.
So each child shall get 1 apple, 2 chikoos & 1 peanut.
The options from this question are missing, following are the options:
(a) 1 apple, 2 chickoos, 2 peanuts
(b) 1 apple, 2 chickoos, 1 peanut
(c) 1 apple, 3 chickoos, 2 peanuts
(d) 1 apple, 1 chickoos, 1 peanut
Spent 7p.
Each child gets 1 apple --> Father spent 3p on 3 apples.
Remaining 4p.
Suppose each child gets 2 chickoos --> Father spent 3p on 6 chickoos
Remaining 1p
Now if each child gets 1 peanut --> Father spent 1p on 3 peanuts.
Hence each child gets 1 apple, 2 chickoos, 1 peanut.
Ans: b